Operating system Windows 7
Qcad Version 3.21.2
I am having a problem setting the dimension of a polygon.
First I choose "Shape" from the tool bar
Next, Polygon (two points of a side)
Next, I choose 6 for the number of sides
Next, I click the mouse to position the point of the first side
Next I hit the space bar to access the command line
Next I type "@.75<0" (not entering the ")
The outcome is a six sided polygon with the side length of 1", not .75
I can complete a polygon with a .5" side by entering @.5<0 and get a length of .5"
But I have not been able to get a .75" sided polygon
What is wrong?
How to define the length of a Polygon side
Moderator: andrew
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Always indicate your operating system and QCAD version.
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Always indicate your operating system and QCAD version.
Attach drawing files and screenshots.
Post one question per topic.
Re: How to define the length of a Polygon side
Hi,
following exactly your description - I can't reproduce it. Works like a charm. Could you post an example please. Thanks.
following exactly your description - I can't reproduce it. Works like a charm. Could you post an example please. Thanks.
Work smart, not hard: QCad Pro
Win10/64, QcadPro, QcadCam version: Current.
If a thread is considered as "solved" please change the title of the first post to "[solved] Title..."
Win10/64, QcadPro, QcadCam version: Current.
If a thread is considered as "solved" please change the title of the first post to "[solved] Title..."
Re: How to define the length of a Polygon side
Was not able to find a way to send a picture of the screen with the polygon and the command line. I however did two things.
First I drew another polygon on the drawing with the parameters of @.75<0 and produced a polygon with a side measuring 1" not .754.
Next I opened a new file and again tried to produce the polygon using @.75<0 and got a polygon with a side measuring .75"
Next I went back to the original drawing and closed the drawing and saved it.
Next I opened the drawing up again and again tried the command and got a polygon measuring 1" not .75.
any help?
First I drew another polygon on the drawing with the parameters of @.75<0 and produced a polygon with a side measuring 1" not .754.
Next I opened a new file and again tried to produce the polygon using @.75<0 and got a polygon with a side measuring .75"
Next I went back to the original drawing and closed the drawing and saved it.
Next I opened the drawing up again and again tried the command and got a polygon measuring 1" not .75.
any help?
Re: How to define the length of a Polygon side
Something is different in that drawing and I need to see the dxf/dwg (not a screenshot!) to help effective. If that drawing is confidential PM is also fine.
How to attache a dxf / dwg drawing to a post:
https://www.qcad.org/rsforum/viewtopic.php?f=47&t=3760
How to attache a dxf / dwg drawing to a post:
https://www.qcad.org/rsforum/viewtopic.php?f=47&t=3760
Work smart, not hard: QCad Pro
Win10/64, QcadPro, QcadCam version: Current.
If a thread is considered as "solved" please change the title of the first post to "[solved] Title..."
Win10/64, QcadPro, QcadCam version: Current.
If a thread is considered as "solved" please change the title of the first post to "[solved] Title..."
Re: How to define the length of a Polygon side
@mlwoy:
1) New drawing.
2) Center on 0,0 and show up to 4 units in the x direction
3) Choose Shape Tool
4) Select 2 point Polygon
5) Select Create Polyline, no Fill , no Radius and 6 Corners in top context bar
6) Press SPACEBAR
7) Type 0,0 and ENTER
Type @.75<0 and ENTER (If your drawing in inches then I think you could type @.75"<0)
Polygon created.
1) New drawing.
2) Center on 0,0 and show up to 4 units in the x direction
3) Choose Shape Tool
4) Select 2 point Polygon
5) Select Create Polyline, no Fill , no Radius and 6 Corners in top context bar
6) Press SPACEBAR
7) Type 0,0 and ENTER
Type @.75<0 and ENTER (If your drawing in inches then I think you could type @.75"<0)
Polygon created.
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- Polygon.wmv
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Windows 10